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Take the category of contextual categories with some additional structure corresponding to some type theory and localize it at homotopy equivalences. Let's call the resulting -category the -category of models of the given type theory. If we take the type theory consisting only of identity types, -types, and a unit type, then the -category of models of this type theory is equivalent to the -category of finitely complete small -categories. If we now add -types together with function extensionality, then we should get the -category of locally cartesian closed -categories. This is still a conjecture, but let's assume it's true.
Now, what will happen if we add -types without function extensionality? I don't think we'll get an equivalent -category. Is there some categorical (putative) description of this -category?
I would presume it would be something like "weakly locally cartesian closed -categories".
Hmm, but what's a weakly locally cartesian closed -category?
I would imagine a finitely complete -category for which pullback has a weak right adjoint.
This might be true if we have only -equivalence, but we also have which gives us some form of uniqueness (maybe not the full homotopy contractibility, but still something). This is even more confusing if we add the K axiom. Then we get just 1-categories and the question of uniqueness becomes easier. It seems that we get a bijection between and . So, do we get locally cartesian closed 1-categories even without function extensionality? Something doesn't add up.
Ah, I didn't realize you wanted to keep .
Having but not funext is weird because it means the evaluation map is bijective on definitional-equivalence-classes of terms, but not an equivalence. So semantically, it's hard to see how to represent it without using a framework like model categories that can distinguish between definitional and typal equality.
The only answer I can think of to guess is something like "weakly locally cartesian closed -categories that can be presented by a model category that is actually locally cartesian closed (as a 1-category)".
That sort of answer makes sense in the presence of K too, since a 1-category can also be presented by a model category.