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The nLab page on subersions says "While the category Diff of (finite dimensional) smooth manifolds does not have all pullbacks, the pullback along a submersion always exists. This is because a submersion is transversal to every other smooth map into its codomain. Moreover, submersions are stable under pullback." Why are submersions stable under pullback? I like the recent paper by David Weisbart and Adam Yassine, but it does not answer my question. While I would greatly appreciate an explanation, a pointer to a proof in some article/book would be even better. Thanks!
I don't know a reference, but I would try to prove like this. A smooth map between manifolds By definition gives for each point a linear map, the differential . By definition is a submersion iff for each the differential is an epimorphism.
A commutative square of smooth maps together with any point in the upper left corner (if you now what I mean) induces a commutative square of linear maps. I suspect that if this commutative square of smooth maps is a pullback square, it induces a pullback square of linear maps.
If the last statement is true we're done, because in the category of vector spaces and linear maps, epimorphisms are stable under pullback.
I don’t know a reference off the top of my head either, but here’s a sketch proof: Since a submersion is transversal to any other map, the fiber product of it and any other map exists (see e.g. Lang’s Fundamentals of differential geometry (1999: pp. 31–32)). By the constant rank theorem, every submersion is a smooth fiber bundle (i.e. locally a product projection) (EDIT 2023-10-02: not (globally) a fiber bundle of course!), and product projections are stable under pullback, so pullbacks of submersions are locally product projections (and hence submersions).
Thanks @John Baez and @ʇɐ for your answers! I get the basic idea. Projections from a product are epic and @John Baez said that epimorphisms in Vect are preserved under pullback. Why is this? (So far I only learned how monos/epis are preserved under pullback/pushout)
The first one is a theorem about category theory, the second one is a theorem about Vect. Do you want to try proving it and show us what you tried? do you have an idea where to start
Actually the projection is not epic in Set, so this cannot be a general theorem of category theory. But for vector spaces this is always true.
Honestly I would use the fact that epics are equivalent to surjections in Vec.
and use explicit known constructions for the pullback.
It's not true that a submersion is a fibre bundle: take the map from (-2,1) disjoint union (-1,2) to (-2,2) that is inclusion on each factor.
@Patrick Nicodemus Thanks to your help! I managed to convince myself by means of looking at the elements/vectors. At the start I thought if might again have something to do with an universal property and necessarily got stuck, as your counterexample nicely shows.
It really is a statement about charts on manifolds. A submersion has the property that around every point , there is chart that looks like , where is a chart in around and is a chart in around . Further, in this chart in , the map looks like the projection (this is the underlying map of the linear projection , where these are the vector spaces containing the open sets that are the charts. This means that on the topological space that is the pullback in , one can build charts around each point.
So given , and a point , the chart around it looks like , where is the chart around in the fibre from before, and is a chart around small enough so that lands inside . The map down to is, on this new chart, a projection (and in this way, you can show it is a submersion), and the projection map to is given on the chart by the product . These two maps are smooth.
One has to check all the details here, of course, but this is how it goes.