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Stream: learning: questions

Topic: a simple 2-categorical exercise


view this post on Zulip Ambroise (Oct 11 2023 at 16:53):

Hello, I am trying to improve my 2-categorical skills with the following exercise: prove that if a category B has an initial object b, then a natural transformation α\alpha between a constant functor from B and another one is uniquely determined by its component αb\alpha_b. This is easy to show directly, but is there a 2-categorical proof of that relying on some adequate notions of an object of a 2-category with an initial object and similar stuff?

view this post on Zulip Patrick Nicodemus (Oct 11 2023 at 19:30):

I don't know how standard this is, but I have recently been working with 2-categories a lot, and a useful definition for my purposes is
that if A\mathcal{A} is a given 2-category and XX is an object in A\mathcal{A}, XX has an initial object if the category A(Y,X)\mathcal{A}(Y,X) has an initial object for every YY, and these initial objects are preserved under the functors A(Y,X)A(Z,X)\mathcal{A}(Y,X)\to\mathcal{A}(Z,X) given by reindexing. In some cases it might be useful to use the stronger definition that there is a specific choice of terminal object in each category A(Y,X)\mathcal{A}(Y,X) and these specific choices are preserved under reindexing. Such a specific choice of section would correspondto the 2-presheaf A(,X)\mathcal{A}(-,X) having a "global section" from the terminal presheaf 1:ACat\mathbf{1}:\mathcal{A}\to\mathbf{Cat} which sends everything to the terminal category.

view this post on Zulip Patrick Nicodemus (Oct 11 2023 at 19:33):

I'm not sure that clarifies the proof so much as it gives a way to extend your proof to other 2-categories by bootstrapping it.

view this post on Zulip Ambroise (Oct 12 2023 at 07:33):

Thanks! I am not sure how to complete the proof, knowing this property. How would you proceed?

view this post on Zulip Kengo Hirata (Oct 12 2023 at 15:09):

I have a 2-categorical proof with a 2-terminal object 1.
First, observe that a category with an initial object is an object BB in Cat\mathbf{Cat} with an adjunction b!:1Bb\dashv ! : 1 \rightarrow B.
Then, from the mate correspondence, a 2-cell b!fb \circ ! \Rightarrow f is bijective to !!f! \Rightarrow !\circ f which is unique by the definition of terminal object.

view this post on Zulip Patrick Nicodemus (Oct 12 2023 at 15:15):

What I meant is the following. I don't insist this is the unique or most natural way to adapt this to 2-categories, just what came to mind.

Let Y,XY,X be objects in our 2-category A\mathcal{A}. Let a,b:YXa, b : Y\to X and τ:ab\tau :a\Rightarrow b. Assume A\mathcal{A} has a 2-terminal object 1\mathbf{1} and that aa and bb both factor through the 2-categorical object by 1-cells a,b:1Xa', b' : \mathbf{1}\to X.

Now let ZZ be arbitrary and j:ZYj : Z\to Y. We have an initial object 0A(Z,Y)0 \in \mathcal{A}(Z,Y) and an initial map e:0je : 0\Rightarrow j.
By some basic theorems about the naturality of whiskering, we have that beτ0:a0b0bj=τjae:a0ajbjb\cdot e\circ \tau\cdot 0 : a\cdot 0\Rightarrow b\cdot 0\Rightarrow bj = \tau\cdot j\circ a\cdot e : a\cdot 0\Rightarrow a\cdot j\Rightarrow b\cdot j.

Because a,ba,b factor through the terminal object, aj=a0a\cdot j =a\cdot 0 and aea\cdot e is the identity 2-cell, and similarly b0bjb\cdot 0\Rightarrow b\cdot j is the identity 2-cell. This forces τ0=τj\tau\cdot 0 = \tau\cdot j. Thus τj\tau\cdot j is determined by τ0\tau\cdot 0.
The intuition here is that τj\tau\cdot j is the component of τ\tau on the "generalized object" jj. One can always take jj to be the identity 1-cell on YY, and then you get a particularly strong instance of this claim, that τ\tau itself is completely determined by τ0\tau\cdot 0.

view this post on Zulip Ambroise (Oct 12 2023 at 18:05):

Thank you both! I think I got the idea.