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The usual definition of the class of "strong epimorphisms" in a completely general category is : a "strong epi" in is an epi which, in addition, is also left orthogonal to all monos.
The conditions under which asking to be an epi is redundant are, however, extremely weak: it is enough for to have equalizers, and in fact it seems to be enough that the diagonal exists, and that is orthogonal to it, to ensure is an epimorphism.
How to build a counterexample, then? Can one find a (possibly finite) category such that there exists a , which is not an epimorphism, and yet ?
Does this work? Take the free category on the graph [image], subject to the relations , , , , chosen in order to make not an epi, and not monos; in particular, , , etc.: so, is not an epi, and there are no nontrivial lifting problems to solve against the monos (for example, the arrows are vacuously mono, but is empty).
Is there a simpler counterexample?
Man if you dont have products, are you even a category?
Products, in this economy!
I don't think you need the objects to be distinct, so you could have fewer arrows, but conceptually this is pretty much the simplest example: you need enough arrows around to stop the relevant ones from being epi/mono, after all.