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Stream: learning: questions

Topic: Freeness and monics


view this post on Zulip Fabrizio Romano Genovese (Mar 28 2024 at 14:04):

I have a very simple question:
The definition of monic morphism is: fg=fh    g=hf \circ g = f \circ h \implies g = h. Now take a free category generated from a graph. The only morphisms we have around are:

Here equality is almost at the typographical level, the only equations we enforce are associativity and identity laws. So am I correct in thinking that any morphism in a free category is vacuously monic, since basically the only equalities we have are between stuff that is _boringly_ equal?

If that's so, does it hold also for freely generated symmetric/commutative monoidal categories?

view this post on Zulip Morgan Rogers (he/him) (Mar 28 2024 at 14:14):

Yes, morphisms in free categories are both monic and epic (for instance, the free monoid on n generators, which is the free category on n endomorphisms, is both left and right cancellative). The same is true for the free monoidal category... but with symmetry you have to be more careful: is ff;τ=fff \otimes f ; \tau = f \otimes f, for τ\tau a transposing two copies of the same object?

view this post on Zulip Peva Blanchard (Mar 28 2024 at 14:18):

Regarding composition, I think it comes down to the fact that the free category generated by a graph can be explicitly described as follows:

view this post on Zulip Fabrizio Romano Genovese (Mar 28 2024 at 14:47):

Morgan Rogers (he/him) said:

Yes, morphisms in free categories are both monic and epic (for instance, the free monoid on n generators, which is the free category on n endomorphisms, is both left and right cancellative). The same is true for the free monoidal category... but with symmetry you have to be more careful: is ff;τ=fff \otimes f ; \tau = f \otimes f, for τ\tau a transposing two copies of the same object?

Generally, no. The best one can say is ff;τ=τ;fff \otimes f ; \tau = \tau ; f \otimes f. But it is indeed ff;τ=fff \otimes f; \tau = f \otimes f if the category is commutative monoidal. But in that case τ=id\tau = id by definition, so I don't think this is very problematic...

view this post on Zulip Morgan Rogers (he/him) (Mar 28 2024 at 17:25):

That sounds right to me on further thought, at which point everything is both monic and epic in these cases too!