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How can one express, formally, the composition of two profunctors in terms of the corresponding two-sided discrete fibrations of categories?
The simplest way is to compose them as spans and then take the discrete reflection.
I guess I deserve this answer for not actually asking the real question I'm interested in :)
Given two functors and , I can take the comma categories and with the associated two-sided fibrations, which are a kind of "non-discrete" version of the two-sided discrete fibrations classifying representable profunctors induced by and .
I would like to understand the relation between the composite span of these two, with tip , and the comma . Explicitly, the latter seems to be a “coend-y” quotient of the first with respect to a two-sided action of morphisms of , so the relation between the two is very similar to the discrete case; but of course, since the latter is not discrete, it cannot be obtained as a discrete reflection.
I asked about the “discrete” case because it was a quicker question to ask, but actually I would like to know if there is an answer that also applies to this non-discrete variant. :)
I'm pretty sure comma categories are discrete two-sided fibrations. The fiber of over and is , which is a discrete set.
Oh, I got confused by the fact that the individual legs of a two-sided discrete fibration are not themselves discrete.
(I was working under the erroneous assumption that the "discrete" span has as tip the "connected components of slices" category that shows up in the comprehensive factorisation of a functor.)
Do you know a reference about the discrete reflection for two-sided spans, whether the discrete two-sided fibrations are the right class of a wfs, etc? The nLab was not enlightening.
Those are all about general 2-categories.
Discrete fibrations and discrete opfibrations are the right classes of the [[comprehensive factorization system]] and its dual, but I don't even know what that would mean in the two-sided case, since a two-sided fibration is a span rather than a morphism.
Discrete morphisms are the right class of some kind of factorization system, that's the "modulated" approach.