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I'm just doing some internal category theory, and was wondering if there is such a thing as a change of basis of the underlying ambient categories, that is to say, turn into . I can't seem to find any resources on such.
The fact that pullback preserving functors V -> W induce functors between categories of internal categories does sometimes get handwaved. There is some stuff on internal categories in Part B of Sketches of an Elephant, iirc, so maybe you'll find the background you need there.
Elaborating on what Morgan said, and if I understand your question correctly, the theory of categories is a finite-limit theory (aka essentially algebraic theory, aka cartesian theory in the Elephant), so a category internal to a category with finite limits is the same thing as a finite-limit-preserving functor , where is the syntactic category of . Thus, if is another category with finite limits, any finite-limit-preserving functor sends a category internal to to a category internal to , by postcomposition. However, this is too general to say anything specific about internal categories, so maybe the part of the Elephant that Morgan pointed to contains more specific remarks.
Here's a slick way to see it. Since spans compose by pullback, it is pretty direct to see that a pullback-preserving functor induces a (pseudo) double functor . Then, since an internal category in is a lax double functor , you just need to post-compose to change the ambient category from to .
Evan Patterson said:
Then, since an internal category in is a lax double functor , you just need to post-compose to change the ambient category from to .
Where is this result from?
I don't know, but Evan will.
This result is connected to two perhaps more well-known results:
A monad in a bicategory is the same as a lax monoidal functor .
A category is a monad in the bicategory .
But it would follow from two related claims - maybe someone can let me know if these are true or whether I'm just confused:
1'. A monad in a double category is the same as a lax double functor .
2'. A category internal to a category with finite limits is the same as a monad in the double category .
Okay, 2'. is Example 2.6 in here:
and I wouldn't be shocked if 1'. were also in there.
I think you’ll also find this all explained in Evan’s recent paper with Lambert, which is all about lax functors into spans giving you cool models of things. https://arxiv.org/abs/2310.05384
One thing I've always wondered about is how to construct the bicategory Span(V), for V a category of finite limits (or more generally with pullbacks), using purely category theoretic constructions. That is, how can I represent Span(V) using universal properties, limits, adjunctions, etc. with respect to V? And also importantly, can this construction generalize beyond Cat into DblCat so that we can construct double categories of spans? I believe I saw somewhere that the subcategory of Prof on discrete categories gives Span(Set), but this approach does not seem very generalizable, though maybe there is a way of generalizing it?
John Onstead said:
One thing I've always wondered about is how to construct the bicategory Span(V), for V a category of finite limits (or more generally with pullbacks), using purely category theoretic constructions. That is, how can I represent Span(V) using universal properties, limits, adjunctions, etc. with respect to V? And also importantly, can this construction generalize beyond Cat into DblCat so that we can construct double categories of spans? I believe I saw somewhere that the subcategory of Prof on discrete categories gives Span(Set), but this approach does not seem very generalizable, though maybe there is a way of generalizing it?
See Dawson–Paré–Pronk's two papers on this topic:
Categories of spans are especially nice in that they have two universal properties, one for mapping out of — this is the one mentioned by by Nathanael Arkor — and one for mapping into (which is the one more useful for constructing monads in spans). The latter says that a functor from a (not double!) category into is the same thing as a functor from the twisted arrow category (the category whose objects are arrows of , and morphisms are factorisations of arrows) into satisfying the condition that for any composable triple in we have .
Because of this condition this doesn't quite express as a right-adjoint — or relative right-adjoint I guess, if you want as a double category and not just its horizontal/loose category — but it can be refined into one if you see (and also ) as what's called a “category with directions” or “adequate triple” (because their morphisms are the functors having this pullback condition).
David Kern said:
Because of this condition this doesn't quite express as a right-adjoint — or relative right-adjoint I guess, if you want as a double category and not just its horizontal/loose category — but it can be refined into one if you see (and also ) as what's called a “category with directions” or “adequate triple” (because their morphisms are the functors having this pullback condition).
Is there a reference for this?
I unfortunately do not have any 1-categorical reference for this, only -categorical (it was certainly known before for 1-categories, but I do not know that it was written down anywhere, possibly because 1-categories of spans are easy enough to manipulate by hand that looking that deeply into things wasn't as necessary). So going to what I do know, adequate triples and their span -categories seem to have first appeared in Barwick's paper on spectral Mackey functors (under the name of effective Burnside -category, in Definition 5.10), and the adjunction itself was worked out in an appendix of Sam Raskin's PhD thesis (section 20). I would say that a more “definitive” reference is Haugseng–Hebestreit–Linskens–Nuiten's recent paper on fibrations and spans (section 2), redoing everything in a much clearer and precise way (they only write it for the -categories of spans, but I think it's easy enough to see that their arguments generalise straightforwardly to the double -categories of spans).
Ah, I see, thank you!