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Stream: learning: questions

Topic: Cauchy in terms of convergence


view this post on Zulip Gurkenglas (Oct 25 2022 at 22:11):

https://ncatlab.org/nlab/show/Cauchy+sequence says

A Cauchy sequence is an infinite sequence which ought to converge in the sense that successive terms get arbitrarily close together, as they would if they were getting arbitrarily close to a limit.

and then gives context-dependent definitions. Could one define Cauchy as "this converges in some extension", then list the "definitions" as examples?

view this post on Zulip Oscar Cunningham (Oct 26 2022 at 07:13):

Yes, in a metric space a sequence is Cauchy if and only if it converges in the completion of the space. I don't know if this extends to the more general contexts on that page.

If you want to make a change to the nLab then a better place to discuss it would be the nForum.

view this post on Zulip Peter Arndt (Oct 26 2022 at 07:38):

To define the completion you usually use equivalence classes of Cauchy sequences. If you want to define Cauchy sequences in terms of the completion, you need to come up with a way to avoid circularity.

view this post on Zulip Gurkenglas (Oct 26 2022 at 11:13):

I don't think this is circular. For Q, "a sequence N->Q is Cauchy iff there exists a distance-preserving Q->Z such that the N->Z converges" is equivalent to the usual definition of Cauchy in a metric space, and then the Cauchy completion proceeds as usual.

view this post on Zulip Gurkenglas (Oct 26 2022 at 11:15):

(Cauchy sequences would be defined equivalent iff they converge through the same choices of Q->Z.)

view this post on Zulip Gurkenglas (Oct 26 2022 at 11:20):

(I suspect you can define the Cauchy completion as the colimit of all initial (aka each Z adds at most one point to Q) such Q->Z.)

view this post on Zulip Oscar Cunningham (Oct 26 2022 at 11:48):

Neat. Wouldn't it be neater to just define the Cauchy completion as the left adjoint to the forgetful functor from complete spaces?

view this post on Zulip Mike Shulman (Oct 26 2022 at 15:31):

I think what Peter was saying is that it's not clear how to prove that those are equivalent definitions of Cauchy-ness if you don't already know that a completion exists.

view this post on Zulip Mike Shulman (Oct 26 2022 at 15:33):

It is possible to construct completions in other ways, though, such as by a Yoneda embedding.

view this post on Zulip Gurkenglas (Oct 26 2022 at 22:00):

@Oscar Cunningham, "complete space" is defined using Cauchy. Or do you mean that we define Cauchy as "converges in some extension", then define "complete", then define the Cauchy completion as that left adjoint? Seems sensible enough. Is there some way to tell from the adjunction that the completion can be constructed as the above colimit of initial Q->Z? Some of that we get from the forgetful functor being full and faithful.

view this post on Zulip Gurkenglas (Oct 26 2022 at 22:23):

@Mike Shulman: That a converging sequence is usual-Cauchy is known. For a usual-Cauchy N->Q, construct N{}Q{} \N \cup \{\infty\} \rightarrow \mathbb{Q} \cup \{\bullet\} to still be usual-Cauchy, and the sequence converges to \bullet since the distance to \bullet vanishes as the upper bounds from usual-Cauchy do.

Oh huh yes, Lawvere metric spaces (categories with each homset replaced by a distance) make the Cauchy completion just be "presheaves with infimum 0". Neat. (Might need to say "groupoids" instead of "categories" to get the presheaf to respect both modes of the triangle inequality.)

view this post on Zulip David Michael Roberts (Oct 27 2022 at 02:46):

Gurkenglas said:

I don't think this is circular. For Q, "a sequence N->Q is Cauchy iff there exists a distance-preserving Q->Z such that the N->Z converges" is equivalent to the usual definition of Cauchy in a metric space, and then the Cauchy completion proceeds as usual.

So N is the natural numbers, Q is the rationals, but Z is not the integers?

view this post on Zulip Mike Shulman (Oct 27 2022 at 02:58):

Gurkenglas said:

Mike Shulman: That a converging sequence is usual-Cauchy is known. For a usual-Cauchy N->Q, construct N{}Q{} \N \cup \{\infty\} \rightarrow \mathbb{Q} \cup \{\bullet\} to still be usual-Cauchy, and the sequence converges to \bullet since the distance to \bullet vanishes as the upper bounds from usual-Cauchy do.

Yes, that's true -- you can essentially construct just enough of the completion to characterize Cauchyness of any particular sequence.

view this post on Zulip Gurkenglas (Oct 28 2022 at 11:53):

Mike Shulman said:

just enough

When a fit is this lucky, there's surely a perspective from which it's not luck. Can you tell of another situation whose lucky fit looks the same, and describe what all such situations have in common?

view this post on Zulip Mike Shulman (Oct 28 2022 at 14:42):

I didn't use the word "lucky".

view this post on Zulip Morgan Rogers (he/him) (Oct 28 2022 at 16:32):

The inclusion of N\N into N{}\N \cup \{\infty\} with the right metric/topology is weakly universal amongst one-point extensions. Completeness is injectivity with respect to that map

view this post on Zulip Mike Shulman (Oct 28 2022 at 17:06):

Although that's more sensitive to the sequential nature of metric spaces than most of the things we've been saying; many of them work just as well for Cauchy nets/filters and completion of uniform spaces.

view this post on Zulip Morgan Rogers (he/him) (Oct 28 2022 at 20:55):

Right, you'd probably want to expand the singleton family of morphisms to a class of "completions of nets" for a more generic setting.

view this post on Zulip Mike Shulman (Oct 28 2022 at 21:00):

And you may get some qualitatively different behavior for size reasons, as there are a proper class of such "completions of nets".