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Stream: learning: questions

Topic: CT Topology


view this post on Zulip Gurkenglas (Sep 02 2021 at 11:50):

I was wondering why it's the preimage of an open set that's open. So I went "a topology is a nice (A->Bool)->Bool, a continuous function is an A->B such that the obvious triangle has the obvious 2-cell" and that made sense of it. Is there prior work on such an approach to topology?
(Is this the right place to ask this?)

view this post on Zulip Zhen Lin Low (Sep 02 2021 at 12:04):

I suppose that's one way to think about it. But you could equally well define a continuous map to be a map such that the image of the closure is contained in the closure of the image, for every subset of the domain.

view this post on Zulip Gurkenglas (Sep 02 2021 at 17:13):

Does that keep working when the above obvious 2-cell is a 2-isomorphism or we replace Bool with some other preorder?

view this post on Zulip Gurkenglas (Sep 02 2021 at 17:18):

image.png okay yep that's how you do topology, i concede :)

view this post on Zulip John Baez (Sep 02 2021 at 17:47):

Gurkenglas said:

I was wondering why it's the preimage of an open set that's open.

One simple point is that given a map between sets, preimage preserves intersection, union and complement, while image preserves only union. So preimage is just much better to work with!

view this post on Zulip Joe Moeller (Sep 02 2021 at 17:53):

It's funny, I see the motivations here backwards from this. The definition of continuous map between Euclidean spaces is clearly what it has to be. Generalizing to metric spaces is not hard. Then if you want to define the notion of general topology, you should look at what continuous maps are like and ask yourself what structure they preserve.

view this post on Zulip John Baez (Sep 02 2021 at 18:02):

That's very reasonable. But then you have to wonder why maps between topological spaces have their preimage preserving open sets, maps between measurable spaces have their preimage preserving measurable sets, and so on - why is the preimage better than the image?

And one answer is that in every case we want to do arguments involving intersections, unions and complements, and how they transform under maps. These operations are all preserved by preimage, but not by image.

In category theory we generalize this insight in many ways....

But one basic idea is that subsets of various kinds (open, measurable, etc.) form "algebras" of various kinds (boolean algebras, Heyting algebras, σ\sigma-algebras, etc.) under operations like intersection, union and complement. And maps between these algebras go in the opposite direction from the maps between spaces. So we get a bunch of dualities between "geometry" and "algebra".

view this post on Zulip Jon Sterling (Sep 02 2021 at 18:05):

To me it likewise has to do with geometry-algebra duality. Notions of space are understood by probing _into_ something that classifies some algebraic data (opens, sheaves, sheaves of modules, etc.); therefore the right notion of morphism will always act on that data by precomposition.

view this post on Zulip Joe Moeller (Sep 02 2021 at 18:11):

Well my point was that preimage is already present in the most basic notion of continuous.
I think the duality of algebra and geometry should be inferred from these sorts of things, not the other way around.

view this post on Zulip Jon Sterling (Sep 02 2021 at 18:12):

I guess I prefer to think about space synthetically, but you are right that there is a reason things turned out to arrange themselves in the way they do.