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Stream: learning: questions

Topic: ✔ The category of monads?


view this post on Zulip Anand Rao (May 12 2023 at 05:34):

For a given category C\mathcal{C}, I was wondering if it is possible to construct a corresponding "category of monads" on C\mathcal{C}. The objects of the category are monads on C\mathcal{C}; given that a monad is a (endo-)functor with additional structure, it makes sense for the morphisms of the category to be natural transformations between the underlying functors with some additional properties. However, a naive approach along these lines presents some problems.

Let TT and SS be monads on C\mathcal{C}, and let η\eta be a natural transformation from TT to SS. Then the "unit" of the monad TT, which is a natural transformation from 1C\mathbb{1}_{\mathcal{C}} to TT, can be post-composed with η\eta to give a natural transformation from 1C\mathbb{1}_{\mathcal{C}} to SS; one can impose the condition that this natural transformation must be equal to the "unit" of the monad SS. This kind of approach seems to fail for the "multiplication" of the monad. The difficulty lies in changing T2T^2 to S2S^2 using η\eta -- one round of application of η\eta transforms T2T^2 to STST, and it does not seem to be possible to simplify this further to S2S^2.

Is it possible to construct a sensible definition of the category of monads on C\mathcal{C} along these lines?

view this post on Zulip Nathanael Arkor (May 12 2023 at 06:11):

The category of monads on a category C\mathcal C is the category of monoids in the strict monoidal category [C,C][\mathcal C, \mathcal C]. If you expand the definitions, you should get the description you are looking for.

view this post on Zulip Dylan Braithwaite (May 12 2023 at 07:17):

Namely the extra step you need is that using the functoriality of SS you get a natural transformation S(η):STSSS(\eta) : ST \Rightarrow SS

view this post on Zulip Anand Rao (May 13 2023 at 03:07):

Ah, I see. Thank you.

view this post on Zulip Notification Bot (May 13 2023 at 03:08):

Anand Rao has marked this topic as resolved.