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Stream: learning: questions

Topic: ✔ Comma Categories vs Categories of Elements


view this post on Zulip Ruby Khondaker (she/her) (Jul 30 2025 at 08:21):

To sum up what I think I learned regarding my original question:

view this post on Zulip Notification Bot (Jul 30 2025 at 08:23):

Ruby Khondaker (she/her) has marked this topic as resolved.

view this post on Zulip Vincent Moreau (Sep 08 2025 at 23:08):

Bryce Clarke said:

Comma categories are examples of categories of elements of a distributor or profunctor. Given a distributor P ⁣:ABP \colon A \nrightarrow B viewed as a functor Aop×BSetA^{\mathrm{op}} \times B \to \mathbf{Set}, its category of elements El(P)\mathbf{El}(P) has objects given by triples (aA,bB,pP(a,b))(a \in A, b \in B, p \in P(a, b)) and morphisms (f,g) ⁣:(a,b,p)(a,b,p)(f, g) \colon (a, b, p) \to (a', b', p') given by morphisms f ⁣:aaf \colon a \to a' in AA and g ⁣:bbg \colon b \to b' in BB such that P(f,1b)(p)=P(1a,g)(p)P(f, 1_{b'})(p') = P(1_{a}, g)(p).

In praise of @Bryce Clarke's message which I found very enlightning a big month ago, let me share a small application of this viewpoint that I hope will illustrate its elegance.

I follow the notations of the quoted message. Let CC be a monoidal category and \bot be an object of CC. We consider the associated category of Chu spaces:

p(f1b)=p(1ag)p' \circ (f \otimes 1_{b'}) \quad=\quad p \circ (1_{a} \otimes g)

This category, of Chu spaces built from CC and \bot, is exactly the category of elements of an appropriate profunctor! namely P:CCopP : C \nrightarrow C^{\mathrm{op}} given by the formula

P(a,b):=C(ab,)P(a, b) \quad:=\quad C(a \otimes b, \bot)

view this post on Zulip Nathanael Arkor (Sep 09 2025 at 08:42):

You should add this observation to the nLab article [[Chu construction]] :)

view this post on Zulip Matteo Capucci (he/him) (Sep 22 2025 at 14:13):

Vincent Moreau said:

This category, of Chu spaces built from CC and \bot, is exactly the category of elements of an appropriate profunctor! namely P:CCopP : C \nrightarrow C^{\mathrm{op}} given by the formula

P(a,b):=C(ab,)P(a, b) \quad:=\quad C(a \otimes b, \bot)

Is this the same as the category of elements of the comma /C×C\otimes / \top \to C \times C?