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Deep down, the reason why the functor Ran_FF is a monad is that you can think Ran_FF as an hom-like construction〈F,F〉
So, the reason why 〈F,F〉is a monad is the same that tells you that the set of self maps End(A) = hom(A,A) for A \in C is a monoid.
This is the ballpark I would try to move into, if I had to find a name for the structure-semantics adjunction, different from "structure-semantics adjunction".
well, i mean a name for its monad, not a name for the adjunction itself
the monad which turns a codensity-monad-admitting functor into a monadic functor
"codensity algebras"?
I'd say codensity modules.
I've been wondering if things where people say 'An X is a Y which is like a Z' are all examples. For example people say that 'A Lie Algebra is a vector space equipped with a bilinear map which is like a commutator'. So are Lie algebras the codensity modules of the commutator functor from the category of associative algebras to the category of vector spaces with bilinear maps? Likewise 'Locales are like the poset of open sets of a topological space', so are locales the codensity modules of ?
'A scheme is a ringed space which is like an affine scheme'?
well, regarding the last one... if we have any poset, we can take the set of completely prime filters and make a topological space, right? does that give a left adjoint to ?
or only to ?
Good point. I think does have a left adjoint in this case, since it preserves limits (although checking that involves thinking about coequalizers in , which make my brain hurt). I think there's an adjoint in my first example too. So these are just trivial examples of codensity monads.
well, i don't know about the others :sweat_smile:
have not thought about them at all
actually, even if that is an adjunction, it just establishes what the codensity monad is—does that tell you that the category of algebras of the codensity monad in question is the category of frames?
I'm trying to work out what the left adjoint actually is. Let be a poset. Then , and is just the total order on two points. So the points of are just all filters of . I can't see what the open set need to be though.
For each element , you can define the set of filters:
You can take these sets as the basis for a topology on the set of filters.
This is the natural topology, in the sense that if is the space of filters, with the above topology, then
.
I didn't check that this is the right topology on , but this would be my best guess.