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Stream: theory: category theory

Topic: monad not preserving epimorphisms


view this post on Zulip Tom Hirschowitz (May 20 2022 at 10:30):

What's an example of a monad not preserving epimorphisms? I'm also interested in the same question with other kinds of epimorphisms (strong, regular,...).

view this post on Zulip Tom Hirschowitz (May 20 2022 at 10:50):

Oh, sorry, that's easy: the free category monad on graphs. [1]+[1][2][1]+[1] \to [2] is epi, but its image is not. (Although it is as a functor...)

view this post on Zulip Morgan Rogers (he/him) (May 20 2022 at 10:54):

Consider the monad on pointed sets defined on objects by AAAA \mapsto A \vee A (wedge product, obtained from disjoint union by identifying basepoints; this is the coproduct of pointed sets), with f:ABf:A \to B mapped to f1f \vee 1 (ff on the left-hand component, everything in the right-hand component mapped to the base-point). We have unit ι1:AAA\iota_1: A \to A \vee A and (ι1ι2)(ι2ι2):(AA)(AA)AA(\iota_1 \vee \iota_2) \vee (\iota_2 \vee \iota_2) : (A \vee A) \vee (A \vee A) \to A \vee A the multiplication.

view this post on Zulip Morgan Rogers (he/him) (May 20 2022 at 11:18):

Tom Hirschowitz said:

Oh, sorry, that's easy: the free category monad on graphs. [1]+[1][2][1]+[1] \to [2] is epi, but its image is not. (Although it is as a functor...)

What constraint are you putting on graphs here? If you mean over the category of directed graphs, the inclusion of the vertices into the graph with one edge is not epic

view this post on Zulip Morgan Rogers (he/him) (May 20 2022 at 11:19):

(because I have two homomorphisms from \bullet \rightarrow \bullet to \bullet \rightrightarrows \bullet)

view this post on Zulip Reid Barton (May 20 2022 at 11:19):

I think [n][n] is a path of nn edges, topologist-style.

view this post on Zulip Reid Barton (May 20 2022 at 11:20):

Another example: We can take the reader monad TX=XATX = X^A. This doesn't work in Set because Set satisfies AC, but it could work in another topos. For instance, we could take TX=XΔ1TX = X^{\Delta^1} on simplicial sets.

view this post on Zulip Morgan Rogers (he/him) (May 20 2022 at 11:20):

Ah I see, sure. Nice example too, @Reid Barton

view this post on Zulip Reid Barton (May 20 2022 at 11:21):

We need a map q:XYq : X \to Y of simplicial sets which is an epimorphism but for which qΔ1q^{\Delta^1} is not epi. For example, we can take Y=Δ1×Δ1Y = \Delta^1 \times \Delta^1 and XX its cover by two disjoint copies of Δ2\Delta^2. Then YΔ1Y^{\Delta^1} has a "characteristic" 1-simplex which does not lift to XΔ1X^{\Delta^1}.