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Let be the category of metric spaces and nonexpansive maps. If is a functor lifting and preserves monomorphisms (i.e. injections), does preserve isometries ?
I haven't been able to prove this nor find a counterexample so I am looking for help.
Aren't isometries isomorphisms?
I think some authors assume isometries are bijection, for me they are only distance preserving maps (they are automatically injective).
Okay. When you say "lifting ", do you mean lifting along the forgetful/underlying set functor?
Yes!
Given an isometry which is not an isomorphism, could we have some silly lifting of the identity functor which is the identity almost everywhere on except that spaces under have their distance function multiplied by a factor of ?
Sorry, one last precision, I am working with metric spaces with distance bounded by 1, or equivalently extended metric spaces.
In your example, the coprojection (coproducts put any two elements in disjoint parts at distance or in the extended case) is not nonexpansive after doing the liting.
No no, is also reduced in distance (it's under itself with the identity morphism)
But is not reduced right?
Huh? You've just given a morphism from to it, so it would be
Oh I didn't understand spaces under like that, so it is any space with a morphism from to it ?
Yes :D
(I don't know if my idea actually works, but I don't think you've broken it yet)
Yeah, but I feel like your example does work :smile:
Thanks
(it doesn't work because there are morphisms between every pair of non-empty metric spaces!!)
But hopefully it at least illustrates why isometries could fail to be preserved?