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Let be categories. Let be a monad. Let be a functor.
Under what, if any, known conditions is the left Kan extension of along a monad?
The right Kan extension of along is always a monad.
Let be the category whose objects are natural numbers and where a morphism is a subset inclusion of consecutive natural numbers in the set .
Let be the functor that sends to the graph with nodes that has an edge from to for each . Let be the functor that sends to the graph with nodes that has an edge from to whenever . It should be the case (I haven't computed this in detail) that the left Kan extension of along is the free category monad on .
If is defined to be the subcategory of where the edge set is either empty or a singleton for all in the graph, then we can define to be the reflexive-transitive closure monad on and it seems plausible that the left Kan extension of this to is also the free category monad. This is what is motivating my question.
Maybe the answer comes from asking : when is the left Kan extension operation strong monoidal with respect to endofunctor composition as opposed to merely being colax monoidal?
In the settings of your question, iT
will always be a relative monad with respect to i
. Theorem 4.6 of monads need not be endofunctors gives sufficient conditions for the resulting left kan extension to be amonad.
Thanks Kenji! Very helpful answer.
(I no longer think my comment about the inclusion of Rel into Graph is correct.)
Patrick Nicodemus said:
Let be categories. Let be a monad. Let be a functor.
Under what, if any, known conditions is the left Kan extension of along a monad?The right Kan extension of along is always a monad.
https://mathoverflow.net/questions/321909/extending-monads-along-dense-functors