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Stream: theory: category theory

Topic: 2-category of nat. transformations between sym. mon. cat.


view this post on Zulip Jean-Baptiste Vienney (Oct 14 2022 at 08:08):

We know that there is a 2-category whose:

Now, if C,D\mathcal{C},\mathcal{D} are two symmetric monoidal categories (in fact, it works with any category C\mathcal{C}), I know that the category [C,D][\mathcal{C},\mathcal{D}] of functors from C\mathcal{C} to D\mathcal{D} and natural transformations between them is a symmetric monoidal category whose:

It follows that the 2-category whose:

is more than a mere 2-category because if I see it as a category SymCAT\bf{SymCAT} enriched over the monoidal category CAT\bf{CAT}, then for every symmetric monoidal categories C,D\mathcal{C},\mathcal{D}, SymCAT[C,D]\bf{SymCAT}[\mathcal{C},\mathcal{D}] is not only a category but a symmetric monoidal category.

What is the best name for this structure?

view this post on Zulip Kobe Wullaert (Oct 14 2022 at 08:44):

It seems to me that your are stating that SymCat is enriched over itself.

view this post on Zulip Jean-Baptiste Vienney (Oct 14 2022 at 08:52):

Oh yes thank you, that's exactly that! So, I have two questions:

view this post on Zulip Kobe Wullaert (Oct 14 2022 at 08:58):

volume 2 of Borceux's handbook of categorical algebra probably has this result. Probably more general, in the sense that any (symmetric, closed) monoidal category is enriched over itself.

view this post on Zulip Jean-Baptiste Vienney (Oct 14 2022 at 09:23):

Thank you very much. But I'm not sure if it is exactly that because what I state is that the cartesian monoidal category of symmetric monoidal categories and functors is enriched over itself so there are two different tensor products in the story. Is it exactly a particular case of what you say? I don't know if I understand it correctly.

view this post on Zulip Kobe Wullaert (Oct 14 2022 at 09:52):

I didn't notice the cartesian part. Then the result I pointed to is indeed not relevant. So you consider SymCAT as full sub 2-category of CAT and you have concluded that that SymCAT inherits the symmetric monoidal structure of CAT? Is this what you mean?

view this post on Zulip Jean-Baptiste Vienney (Oct 14 2022 at 10:34):

I clarified my mind during the discussion. Yes, this is exactly what I mean.

view this post on Zulip Jean-Baptiste Vienney (Oct 14 2022 at 10:55):

I think that what I mean very precisely is that SymCAT as a full subcategory of CAT inherits the cartesian monoidal structure of CAT and is enriched over (SymCAT as a cartesian monoidal category).

view this post on Zulip Jean-Baptiste Vienney (Oct 14 2022 at 11:00):

(and not only over CAT as a cartesian monoidal category like a mere 2-category)

view this post on Zulip Mike Shulman (Oct 14 2022 at 16:14):

You don't want to conisder SymMonCat as a full subcategory of Cat; you want to look at only the (strong) symmetric monoidal functors. In this case you can indeed show that it is a closed symmetric monoidal 2-category, in an appropriate sense, and therefore enriched over itself. The internal-homs are the category of symmetric monoidal functors, with the induced symmetric monoidal structure you describe; the version you indicated that ignores any monoidal structure on the domain is instead the "power" or "cotensor" of SymMonCat over Cat.

view this post on Zulip Mike Shulman (Oct 14 2022 at 16:19):

Abstractly, this works because the 2-monad on Cat whose algebras are symmetric monoidal categories is "pseudo-commutative". This was studied by Hyland and Power in Pseudo-commutative monads and pseudo-closed 2-categories, and later the proof was simplified using skew structures by Bourke in Skew structures in 2-category theory and homotopy theory.

view this post on Zulip Mike Shulman (Oct 14 2022 at 16:21):

Neither the internal-hom nor the tensor product of SymMonCat coincides with the underlying internal-hom or cartesian monoidal structure of Cat.

view this post on Zulip Jean-Baptiste Vienney (Oct 14 2022 at 19:21):

Thank you very much for your explanations and references! That makes a lot for me to learn to have a better grasp on this subject. I'll try to understand all of this. You have clearly solved my problem.

view this post on Zulip Chad Nester (Oct 15 2022 at 09:07):

I found this to be very approachable.